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A.11(A)·Algebra II·Exponential & Logarithmic FunctionsReadiness

Exponential and Logarithmic Relationships

Connect numerical patterns to exponential and logarithmic functions.

Students define a logarithm as an exponent, then use swapped table values and reflected graphs to connect y=bxy=b^x with its inverse, y=log⁡bxy=\log_b x.

Lesson plan and worked examples by TEKSForge · not a TEA-issued lesson. Videos by independent educators.

Archived course: TEKS code and readiness label from TEA's 2013 Algebra II key. Algebra II is not one of Texas's current required STAAR EOC assessments, and this lesson does not change the Biology and Algebra I Study Plans.

Learn the concept

A logarithm is an exponent

For b>0b>0 and b≠1b\ne 1, the statement log⁡bx=y\log_b x=y means exactly the same thing as by=xb^y=x. The common logarithm uses base 10, so log⁡100=2\log 100=2 because 102=10010^2=100. A logarithm answers the question “what exponent is needed?”

Inverses swap ordered pairs

If (2,100)(2,100) is on y=10xy=10^x, then (100,2)(100,2) is on y=log⁡xy=\log x. The graphs are reflections across y=xy=x. The exponential function has domain all real numbers and range y>0y>0; the logarithm reverses them, with domain x>0x>0 and range all real numbers.

Test a proposed rule

When a table claims to show an inverse, check every pair, not just one. A linear rule such as 10x10x may match a single pair, but only the exponential rule 10x10^x reproduces the repeated multiplication by 10.

Worked example

A table for g shows inputs 1, 2, 3 and outputs 3, 9, 27. Write the inverse of g.

  1. Each output is 3 raised to the input, so g(x)=3xg(x)=3^x.
  2. Swap every pair: (3, 1), (9, 2), and (27, 3).
  3. Each swapped pair asks for an exponent on 3; for example, log⁡39=2\log_3 9=2 because 32=93^2=9.

g−1(x)=log⁡3xg^{-1}(x)=\log_3 x

Watch the lesson

Texas public-school, Texas educator-created, and TEKS-aligned lessons, hosted by their creators. Each card names its source.

Texas public school video

Algebra 2 Inverses of Exponential Functions

UT IPSI · Kid2Kid / Texas Education Agency

Connect exponential functions to logarithms by finding and interpreting their inverses.

Watch on YouTube
Texas public school video

Algebra 2 Functions and Their Inverses

UT IPSI · Kid2Kid / Texas Education Agency

Swap inputs and outputs in tables and graphs to identify a function's inverse.

Watch on YouTube

Try it yourself

TEKSForge practice · unscored

  1. 1. Write 10−2=0.0110^{-2}=0.01 in logarithmic form.

    Show answer and reasoning

    log⁡0.01=−2\log 0.01=-2

    The exponent, −2, becomes the output of the base-10 logarithm, and the result of the power, 0.01, becomes its input.

  2. 2. The point (1000,3)(1000,3) is on f(x)=log⁡xf(x)=\log x. What point is on its inverse?

    Show answer and reasoning

    (3,1000)(3,1000)

    Inverse functions swap inputs and outputs. The inverse is y=10xy=10^x, and 103=100010^3=1000.

Released STAAR practice

Texas Education Agency · archived 2013 released EOC items · scored with TEA's answer key; step-by-step explanations written by TEKSForge because this release has no rationales. Original graphs, tables, and diagrams are shown where the released item includes one.

Archived released STAAR Algebra II EOC · 2013 · Item 1 · 1 point

Some values for the function f(x)=log⁡xf(x) = \log x are given in Table 1. Which function can generate all the values in Table 2?

Table 1 and Table 2
TablexFunction values
Table 1: f(x)=log⁡xf(x) = \log x10, 100, 1,000, 10,0001, 2, 3, 4
Table 2: g(x)g(x)1, 2, 3, 410, 100, 1,000, 10,000
Each comma-separated pair lists the x-values and corresponding function values in their original order.
  1. g(x)=x10g(x) = x^{10}
  2. g(x)=10xg(x) = 10^x
  3. g(x)=10xg(x) = \frac{10}{x}
  4. g(x)=10xg(x) = 10x
Show STAAR answer and explanation

g(x)=10xg(x) = 10^x

Evaluate g(x)=10xg(x)=10^x at 1, 2, 3, and 4 to get 10, 100, 1,000, and 10,000. Every table pair matches.

g(x)=x10g(x) = x^{10}: This gives 110=11^{10}=1 and 210=1,0242^{10}=1{,}024, not 10 and 100.

g(x)=10xg(x) = \frac{10}{x}: This decreases as x increases and gives g(2)=5g(2)=5, not 100.

g(x)=10xg(x) = 10x: This gives 10, 20, 30, and 40; the table values multiply by 10 rather than add 10.

Archived released STAAR Algebra II EOC · 2013 · Item 21 · 1 point

What is the inverse of h(x)=12log⁡3(x)h(x) = \frac{1}{2}\log_3(x)?

  1. h−1(x)=3(2x)h^{-1}(x) = 3^{(2x)}
  2. h−1(x)=2(3)xh^{-1}(x) = 2(3)^x
  3. h−1(x)=2(log⁡x3)h^{-1}(x) = 2(\log_x 3)
  4. h−1(x)=log⁡3(2x)h^{-1}(x) = \log_3(2x)
Show STAAR answer and explanation

h−1(x)=3(2x)h^{-1}(x) = 3^{(2x)}

Swap x and y: x=12log⁡3yx=\frac12\log_3 y. Multiply by 2: 2x=log⁡3y2x=\log_3 y. Rewrite in exponential form: y=32xy=3^{2x}.

h−1(x)=2(3)xh^{-1}(x) = 2(3)^x: This multiplies the power by 2 instead of putting 2x2x in the exponent. Since h(9)=1h(9)=1, the inverse must give 9 at x=1x=1, but 2(3)1=62(3)^1=6.

h−1(x)=2(log⁡x3)h^{-1}(x) = 2(\log_x 3): This only changes the base of the logarithm. The inverse of a logarithmic function is exponential.

h−1(x)=log⁡3(2x)h^{-1}(x) = \log_3(2x): This is still a logarithm, so it cannot undo log⁡3\log_3.

Start scored STAAR practice

Learning objectives

By the end of the lesson, students can:

  • Translate between exponential form by=xb^y=x and logarithmic form log⁡bx=y\log_b x=y.
  • Recognize inverse functions in tables by their swapped input-output pairs.
  • Compare the domains, ranges, and asymptotes of y=10xy=10^x and y=log⁡xy=\log x.

Instructional sequence

  1. 1

    Engage

    5 min

    List 10, 100, 1,000, and 10,000. Ask students what exponent on 10 produces each number.

  2. 2

    Direct instruction

    10 min

    Define log⁡bx=y\log_b x=y as “the exponent on b that produces x.” Introduce the common logarithm, log⁡x=log⁡10x\log x=\log_{10}x.

  3. 3

    Guided practice

    12 min

    Complete a table for y=10xy=10^x, then swap its columns to build the table for y=log⁡xy=\log x. Verify each swapped pair with the definition.

  4. 4

    Graph connection

    15 min

    Plot both functions with y=xy=x. Students mark matching reflected points and compare y=0y=0 and x=0x=0 as asymptotes.

  5. 5

    Closure

    8 min

    Students test one proposed inverse rule against every table pair, then complete the exit ticket.

Misconceptions to address

““log⁡x\log x means log multiplied by x.””

Teacher move: Treat log as a function name. Its output is an exponent: log⁡1000=3\log 1000=3 because 103=100010^3=1000.

““The inverse of log⁡x\log x is x10x^{10} or 10x\frac{10}{x}.””

Teacher move: An inverse undoes the original function by swapping each pair. Test the rule: only 10x10^x turns 1, 2, 3 back into 10, 100, 1,000.