Lesson library
G.8(D)·Geometry·Measurement & Three-Dimensional FiguresReadiness

Surface Area and Volume

Calculate surface area and volume for three-dimensional figures in context.

Students calculate surface area and volume of common solids, distinguish lateral from total surface area, and choose the correct radius, perpendicular height, or slant height for each context.

Lesson plan and worked examples by TEKSForge · not a TEA-issued lesson. Videos by independent educators.

Archived course: TEKS code and readiness label from TEA's 2013 Geometry key. Geometry is not one of Texas's current required STAAR EOC assessments, and this lesson does not change the Biology and Algebra I Study Plans.

Learn the concept

Surface area covers the outside

Surface area is the total area of all outside surfaces. It is measured in square units, such as square centimeters. Painting, wrapping, and covering problems use surface area.

Key formulas

For a sphere, SA=4πr2SA=4\pi r^2. For a closed cylinder, SA=2πr2+2πrhSA=2\pi r^2+2\pi rh. For a prism, add the areas of all faces, or use SA=2B+PhSA=2B+Ph, where B is the base area and P is the base perimeter.

Read the context

Convert diameter to radius. Leave out surfaces that are not covered, such as an open top. If several identical objects are involved, multiply one object's surface area by the number of objects.

Volume of prisms and cylinders

Volume measures space inside in cubic units. For any prism, V=BhV=Bh, where B is the area of a base and h is the perpendicular distance between bases. A rectangular prism has V=lwhV=lwh. For a cylinder, B=πr2B=\pi r^2, so V=πr2hV=\pi r^2h. Convert diameter to radius before substituting.

Volume of pyramids, cones, and spheres

A pyramid has V=13BhV=\frac{1}{3}Bh, and a cone has V=13πr2hV=\frac{1}{3}\pi r^2h. Each has one-third the volume of a prism or cylinder with the same base area and perpendicular height. A sphere has V=43πr3V=\frac{4}{3}\pi r^3. A cone's capacity uses its perpendicular height, not the sloping side length.

Lateral area of a square pyramid

A regular square pyramid has four triangular lateral faces. Their combined area is LA=12PℓLA=\frac{1}{2}P\ell, where P is the base perimeter and ℓ\ell is the slant height measured along a face from the apex to the midpoint of a base edge. For base side s, P=4sP=4s. Lateral area excludes the base; total surface area is 12Pℓ+s2\frac{1}{2}P\ell+s^2. The vertical height is not the triangular face's height.

Study released STAAR visuals

Use the original graphs, tables, and diagrams from released STAAR questions to practice reading labels, values, and relationships before answering the items below.

Archived released STAAR Geometry EOC · 2013 · Item 28 · 1 point

An inverted cone. The radius of the circular top is 4.5 centimeters, the dashed perpendicular height from the center of the top to the tip is 6 centimeters, and the slant height along the side is 7.5 centimeters.
Conical paper cupOriginal visual from the released STAAR test.

Archived released STAAR Geometry EOC · 2013 · Item 37 · 1 point

A square pyramid with a dashed vertical height from the apex to the center of the base, a right-angle mark at the base, and a dashed segment from the center of the base to the midpoint of a base edge, showing the slant height along a face.
Square pyramidOriginal visual from the released STAAR test.

Worked example

Three closed cylinders, each with radius 2 inches and height 5 inches, are painted. What total area is painted?

  1. One cylinder: 2π(2)2+2π(2)(5)=8π+20π=28π2\pi(2)^2+2\pi(2)(5)=8\pi+20\pi=28\pi.
  2. Three cylinders: 3(28π)=84π3(28\pi)=84\pi.
  3. Approximate: 84π≈263.984\pi\approx 263.9 square inches.

About 263.9 square inches

Watch the lesson

Texas public-school, Texas educator-created, and TEKS-aligned lessons, hosted by their creators. Each card names its source.

Texas public school video

Geometry: Composite Figures Volume and Surface Area

UT IPSI · Kid2Kid / Texas Education Agency

Find surface area and volume for three-dimensional and composite figures in context.

Watch on YouTube

Try it yourself

TEKSForge practice · unscored

  1. 1. Find the surface area of a sphere with a diameter of 10 centimeters.

    Show answer and reasoning

    100π≈314.2100\pi\approx 314.2 square centimeters

    The radius is 5, so SA=4π(5)2=100πSA=4\pi(5)^2=100\pi.

  2. 2. Find the surface area of a cube with an edge length of 4 inches.

    Show answer and reasoning

    96 square inches

    Each of the six faces has an area of 16 square inches, and 6(16) = 96.

  3. 3. A conical container has radius 3 cm and perpendicular height 10 cm. Find its exact capacity.

    Show answer and reasoning

    30π30\pi cubic centimeters

    V=13π(3)2(10)=30πV=\frac{1}{3}\pi(3)^2(10)=30\pi. Use cubic units because capacity is volume.

  4. 4. A regular square pyramid has base side 12 m and slant height 10 m. Find its lateral surface area.

    Show answer and reasoning

    240 square meters

    The base perimeter is 4(12)=484(12)=48 m, so LA=12(48)(10)=240LA=\frac{1}{2}(48)(10)=240 square meters. Do not add the base.

Released STAAR practice

Texas Education Agency · archived 2013 released EOC items · scored with TEA's answer key; step-by-step explanations written by TEKSForge because this release has no rationales. Original graphs, tables, and diagrams are shown where the released item includes one.

Archived released STAAR Geometry EOC · 2013 · Item 6 · 1 point

Five spheres are being painted for a display at a store. If the diameter of each sphere is 7 centimeters, which value is closest to the total surface area that will be painted?

  1. 770 cm²
  2. 154 cm²
  3. 192 cm²
  4. 440 cm²
Show STAAR answer and explanation

770 cm²

Each radius is 3.5 cm. One sphere has area 4πr2=4π(3.5)2=49π4\pi r^2=4\pi(3.5)^2=49\pi, so five spheres have 245π≈770245\pi\approx770 cm².

154 cm²: 49π≈15449\pi\approx154 cm² is the surface area of only one sphere, not all five.

192 cm²: This does not apply S=4πr2S=4\pi r^2 with radius 3.5 and then multiply by five.

440 cm²: This underestimates 245π245\pi. Use the radius, not the diameter, in 4πr24\pi r^2 and multiply by five.

Archived released STAAR Geometry EOC · 2013 · Item 28 · 1 point

An inverted cone. The radius of the circular top is 4.5 centimeters, the dashed perpendicular height from the center of the top to the tip is 6 centimeters, and the slant height along the side is 7.5 centimeters.
Conical paper cupOriginal visual from the released STAAR test.

A conical paper cup is shown in the diagram. Which value is closest to the maximum volume of water this cup can hold?

  1. 159 cm³
  2. 32 cm³
  3. 127 cm³
  4. 40 cm³
Show STAAR answer and explanation

127 cm³

The radius is 4.5 cm and perpendicular height is 6 cm. Thus V=13π(4.5)2(6)=40.5π≈127.2V=\frac13\pi(4.5)^2(6)=40.5\pi\approx127.2 cm³.

159 cm³: Using slant height 7.5 instead of perpendicular height 6 gives about 159 cm³.

32 cm³: Halving the given radius incorrectly gives about 32 cm³.

40 cm³: This approximates 40.5 but omits the factor of π\pi.

Archived released STAAR Geometry EOC · 2013 · Item 37 · 1 point

A square pyramid with a dashed vertical height from the apex to the center of the base, a right-angle mark at the base, and a dashed segment from the center of the base to the midpoint of a base edge, showing the slant height along a face.
Square pyramidOriginal visual from the released STAAR test.

The main entrance to the Louvre art museum is shaped like a pyramid. The pyramid is 71 feet tall and has a slant height of approximately 91 feet. Each side of the square base measures 115 feet. Which of the following is closest to the lateral surface area of the pyramid?

  1. 20,930 ft²
  2. 16,330 ft²
  3. 10,465 ft²
  4. 34,155 ft²
Show STAAR answer and explanation

20,930 ft²

The lateral area is 12Pl=12(4⋅115)(91)=20,930\frac12Pl=\frac12(4\cdot115)(91)=20{,}930 ft². Lateral area excludes the square base.

16,330 ft²: This uses perpendicular height 71 rather than slant height 91.

10,465 ft²: This counts only two of the four triangular faces.

34,155 ft²: This adds the base area 1152115^2 and gives total surface area, not lateral area.

Start scored STAAR practice

Learning objectives

By the end of the lesson, students can:

  • Apply the sphere surface-area formula SA=4πr2SA=4\pi r^2.
  • Find surface areas of prisms and cylinders by adding the areas of their faces.
  • Decide which surfaces count in a context and scale the result for several objects.
  • Find volumes of prisms, cylinders, pyramids, cones, and spheres, and lateral surface area of regular square pyramids.

Instructional sequence

  1. 1

    Engage

    5 min

    Ask whether painting a ball requires surface area or volume and why.

  2. 2

    Direct instruction

    10 min

    Connect nets to surface-area formulas and introduce the sphere formula with radius.

  3. 3

    Guided practice

    12 min

    Find surface areas for spheres, cylinders, and prisms, converting diameter to radius first.

  4. 4

    Context problems

    12 min

    Solve problems with several identical objects or open surfaces, deciding what counts.

  5. 5

    Volume and pyramid faces

    10 min

    Compare volume formulas, distinguish perpendicular height from slant height, and find a square pyramid's lateral surface area.

  6. 6

    Closure

    6 min

    Complete the exit ticket with square units.

Misconceptions to address

““Use the diameter as r in the formula.””

Teacher move: Divide the diameter by 2 first. Using the diameter makes the surface area four times too large.

““Painting a figure uses its volume.””

Teacher move: Paint covers the outside, so it is measured in square units. Volume measures space inside in cubic units.

““Height means the same segment in every formula.””

Teacher move: Volume uses perpendicular height. A regular pyramid's lateral-area formula uses slant height along a triangular face.